100 Days in the Secret Place: Classic Writings from Madame Guyon, Francois Fenelon, and Michael

100 Days in the Secret Place: Classic Writings from Madame Guyon, Francois Fenelon, and Michael

Matematika Q :^


5³ + Lim (6²+ 36³ : 2¹ × 1² )
- 4(6)


1 Km : 2 m = cm

menggunakan tangganya yah :^


nt : mari meyiksa orang yang jawab :^​

Q :^


5³ + Lim (6²+ 36³ : 2¹ × 1² )
- 4(6)


1 Km : 2 m = cm

menggunakan tangganya yah :^


nt : mari meyiksa orang yang jawab :^​

TSATUAN PANJANG :

  1. KILO METER
  2. HEKTO METER
  3. DEKA METER
  4. METER
  5. DESI METER
  6. CENTI METER
  7. MILLI METER

TURUN × 10

NAIK ÷ 10

SOAL :

1) 5³ + LIM ( 6² + 36³ ÷ 2¹ × 1² )

= 125 + ( 6.6 ) + ( 36.36.36 ) ÷ 2 × 1 )

= 125 + ( 36 + 46.656 ÷ 2 × 1 )

= 125 + ( 36 + 46.656 ÷ 2 )

= 125 + ( 36 + 23.328 )

= 125 + 23.364

= 23.489

2) 1 KM ÷ 2 M = CM

= ( 1 × 100.000 ) ÷ ( 2 × 100 )

= 100.000 CM ÷ 200 CM

= 500 CM

[tex]{ \huge{ \mathfrak{ \red{penjelasan : }}}}[/tex]

[tex]{ \color{red}{ \rm{pertanyaan : }}}[/tex]

= 5³ + lim ( 6² + 36³ ÷ 2¹ × 1² )

= ?

1 km ÷ 2 m = cm ?

========================================

[tex]{ \huge{ \mathfrak{ \blue{pembahasan : }}}}[/tex]

= 5³ + ( 6² + 36³ ÷ 2¹ × 1² )

= 23.489

_______________

5³ = 5 × 5 × 5

= 25 × 5

= 125

________________

6² = 6 × 6

= 36

________________

36³ = 36 × 36 × 36

= 1.296 × 36

= 46.656

________________

= 125 + ( 36 + 46.656 ÷ 2 × 1 )

= 125 + ( 36 + 23.328 × 1 )

= 125 + 23.364

= 23.489

==================================

SATUAN PANJANG

  • Kilo meter
  • hekto meter
  • deka meter
  • meter
  • desi meter
  • centi meter
  • mili meter

= 1 KM ÷ 2 M = 500 CM

= ( 1 × 100.000 ) ÷ ( 2 × 100 )

= 100.000 ÷ 200

= 500 CM

[tex]{ \huge{ \mathfrak{ \blue{by : akbar}}}}[/tex]

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